Difference between revisions of "Construct a pentagon/admin"
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* <code>{{:[[Construct a pentagon/eq]]|01}}</code> | * <code>{{:[[Construct a pentagon/eq]]|01}}</code> | ||
* <code>{{[[Template:varphi|varphi]]}}</code> | * <code>{{[[Template:varphi|varphi]]}}</code> | ||
+ | |||
+ | == Math == | ||
+ | |||
+ | If the math / LaTeX module is installed, these should display: | ||
+ | |||
+ | 01 <math> \frac\mbox{NO + ND}\mbox{NO} = \frac\mbox{NO}\mbox{ND}</math> | ||
+ | 02 <math> \frac{\frac{s}{t} + \frac{t}{t}}{\frac{s}{t}} = \frac{s}{t} </math> | ||
+ | 03 <math> \frac{\varphi + 1}{\varphi} = \varphi </math> | ||
+ | 04 <math> \frac{s+t}{s} = \frac{s}{t} </math> | ||
+ | 05 <math> \varphi + 1 = \varphi^2 </math> | ||
+ | 06 <math>\varphi^2 - \varphi - 1 = 0</math> | ||
+ | 07 <math>{ax}^2 - {bx} - {c} = 0</math> | ||
+ | 08 <math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a} </math> | ||
+ | 09 <math>x = \frac{-(-1) \pm \sqrt {(-1)^2-4(1)(-1)}}{2(1)} </math> | ||
+ | 10 <math>\varphi = {1 \pm \sqrt{5} \over 2}</math> | ||
+ | 11 <math>\varphi = {1 + \sqrt{5} \over 2} | ||
+ | 12 <math> \frac{\varphi}{\varphi} + \frac{1}{\varphi} = \varphi </math> | ||
+ | 13 <math> 1 + \frac{1}{\varphi} = \varphi </math> | ||
+ | 14 <math> \frac{1}{\varphi} = \varphi - 1 </math> | ||
+ | 15 <math> \mbox{DA}' = {g} = \frac{1}{\varphi} = \varphi - 1</math> | ||
+ | 16 <math>\mbox{MA}' = \sqrt {\left(\frac{1}{2}\right)^2 + (1)^2} </math> | ||
+ | 17 <math>\mbox{MA}' = \sqrt {\frac{1}{4} + 1} = \sqrt {\frac{5}{4}} = {\sqrt {5} \over \sqrt {4}}</math> | ||
+ | 18 <math>\mbox{MA}' = {\sqrt {5} \over {2}}</math> | ||
+ | 19 <math>\mbox{PA}' = {\sqrt {5} \over {2}} + \frac{1}{2} = {1 + \sqrt{5} \over 2}</math> | ||
+ | 20 <math>\mbox{QA}' = {\sqrt {5} \over {2}} - \frac{1}{2}</math> | ||
+ | 21 <math>\mbox{QA}' = {\sqrt {5} \over {2}} + \left(\frac{1}{2} - \frac{1}{2}\right) - \frac{1}{2}</math> | ||
+ | 22 <math>\mbox{QA}' = {1+\sqrt {5} \over {2}} - \frac{1}{2} - \frac{1}{2}</math> | ||
+ | 23 <math>\mbox{QA}' = {1+\sqrt {5} \over {2}} - 1</math> | ||
+ | 24 <math>\mbox{AB} = \sqrt {{5-\sqrt {5} \over {2}}}</math> |
Latest revision as of 15:13, 25 June 2006
Subpages
- Construct a pentagon
- Construct a pentagon/admin
- Construct a pentagon/nav
- Construct a pentagon/gallery
- Construct a pentagon/
- Construct a pentagon/
Toolbox
{{:Construct a pentagon/nav}}
{{:Construct a pentagon/eq|01}}
{{varphi}}
Math
If the math / LaTeX module is installed, these should display:
01 <math> \frac\mbox{NO + ND}\mbox{NO} = \frac\mbox{NO}\mbox{ND}</math> 02 <math> \frac{\frac{s}{t} + \frac{t}{t}}{\frac{s}{t}} = \frac{s}{t} </math> 03 <math> \frac{\varphi + 1}{\varphi} = \varphi </math> 04 <math> \frac{s+t}{s} = \frac{s}{t} </math> 05 <math> \varphi + 1 = \varphi^2 </math> 06 <math>\varphi^2 - \varphi - 1 = 0</math> 07 <math>{ax}^2 - {bx} - {c} = 0</math> 08 <math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a} </math> 09 <math>x = \frac{-(-1) \pm \sqrt {(-1)^2-4(1)(-1)}}{2(1)} </math> 10 <math>\varphi = {1 \pm \sqrt{5} \over 2}</math> 11 <math>\varphi = {1 + \sqrt{5} \over 2} 12 <math> \frac{\varphi}{\varphi} + \frac{1}{\varphi} = \varphi </math> 13 <math> 1 + \frac{1}{\varphi} = \varphi </math> 14 <math> \frac{1}{\varphi} = \varphi - 1 </math> 15 <math> \mbox{DA}' = {g} = \frac{1}{\varphi} = \varphi - 1</math> 16 <math>\mbox{MA}' = \sqrt {\left(\frac{1}{2}\right)^2 + (1)^2} </math> 17 <math>\mbox{MA}' = \sqrt {\frac{1}{4} + 1} = \sqrt {\frac{5}{4}} = {\sqrt {5} \over \sqrt {4}}</math> 18 <math>\mbox{MA}' = {\sqrt {5} \over {2}}</math> 19 <math>\mbox{PA}' = {\sqrt {5} \over {2}} + \frac{1}{2} = {1 + \sqrt{5} \over 2}</math> 20 <math>\mbox{QA}' = {\sqrt {5} \over {2}} - \frac{1}{2}</math> 21 <math>\mbox{QA}' = {\sqrt {5} \over {2}} + \left(\frac{1}{2} - \frac{1}{2}\right) - \frac{1}{2}</math> 22 <math>\mbox{QA}' = {1+\sqrt {5} \over {2}} - \frac{1}{2} - \frac{1}{2}</math> 23 <math>\mbox{QA}' = {1+\sqrt {5} \over {2}} - 1</math> 24 <math>\mbox{AB} = \sqrt {{5-\sqrt {5} \over {2}}}</math>